A = \sqrt{16(16 - 10)(16 - 10)(16 - 12)} = \sqrt{16(6)(6)(4)} = \sqrt{2304} = 48

Sat, 09 May 2026 03:06:44 +0000

Understanding the Algebraic Expression: A = √[16(16 – 10)(16 – 10)(16 – 12)] = 48 Calculus and algebra often intersect in powerful ways, especially when solving expressions involving square roots and polynomials. One such elegant example is the algebraic identity: A = √[16(16 – 10)(16 – 10)(16 – 12)] = √[16 × 6 × 6 × 4] = √2304 = 48 This expression demonstrates a common technique in simplifying square roots, particularly useful in geometry, physics, and advanced algebra. Let’s break it down step-by-step and explore its significance.