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Home » First, compute \(f(3)\): - Roya Kabuki

First, compute \(f(3)\): - Roya Kabuki

📅 May 8, 2026 👤 scraface

May 08, 2026

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\frac{6!}{3! \cdot 2! \cdot 1!} = \frac{720}{6 \cdot 2} = \frac{720}{1...
Now, subtract the number of arrangements where the two N's are adjacen...
Treat the two adjacent N's as a single block "NN". Then we are arrangi...
Number of such arrangements:
Therefore, the number of arrangements where the two N's are **not adja...
- 20 = 40
Thus, the number of valid distinct arrangements is:
\boxed{40}
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